A 1.20-kg skateboard is coasting along the pavement at a speed of 5.00 m/s when a 0.800- kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination? (Remember that momentum is a vector and that conservation of momentum is a vector equation that is applied separately in x- and y- directions) mc=0.8 kg BEFORE (Ptotal=+6 kg m/s) AFTER V=5.0m/s m = 1.2kg ms+mc v'=?