A) B) Find the equation of the line tangent to the graph of x + y = (-3,-1). The equation of the tangent line is y C) E) D) Write the equation of the line tangent to the graph of y = -9y - 2x - 12 at (1,-2). The equation is y= dy Find for y = dx dy dx sin(4x) 8e5x Let f(x) = ln (7x - 2x - 3) f'(x) = = -4xy - 16 at Let f(x) = (-3x + 8x + 2)e-5. Then f'(x) = F) G) H) 1) J) Let f(x) = 2x5x +9. Find the equation of the line tangent to the graph of y = f(x) at the point (3, 18). The equation of the tangent line is y = Let f(x) = x(x-7)5 (x+7) Use logarithmic differentiation to determine the derivative. f'(x) = If y = (3x), then dy dx (Be sure to express your answer in terms of x) Find the derivative: d dx (cos(3x + 3)) = Use implicit differentiation to find y + 5x = 3y - 6x dy da dy dx K) L) Find the derivative: d dx M) N) (sin(3x + 4)) = dy Find where dx y ln (x) - 4x4 - y = 7 dy dx Find dy dx dy dx for y= = sin (3x) 9-x5 If y = (5x) sin(2x), then dy dx (Be sure to express your answer in terms of x)