A block of mass m = 1 kg is released from rest at the top of a smooth hemispherical bowl of radius R = 2 m. Lying at the bottom of the bowl there is a second block of mass m = 3 kg. Assuming the surface of the bowl is frictionless, find: If the masses stick together after they collide, how high above the bottom of the bowl will the two masses go before starting to slide back down? O 0.25 m O 1m O 0.125 m O 2m O 0.5 m D Question 10 1 pts Following the last problem. Assume all the energy of the first block is transferred into the second block during collision (ignore conservation of momentum), how high above the bottom of the bowl will the second mass go before starting to slide back down? O 0.5 m 0.66 m O 0.33 m O 0.01 m