A CaCO-filled substrate is being used to neutralize acid. How much of the total substrate would it take to neutralize 250 mL of acid water? Determine the rate of reaction for the CaCO within the substrate to neutralize the acid.

Given:

• CaCO3 component density = 2.7 g/cm^3
  • 70% wt volume of blend
  • 25.92 cm^3 by volume
  • Percent CaCO by volume = 42.65%
    • For example, there is 43% CaCO on the surface of the substrate that is used to neutralize this acid water
• The acid water is complex and uses the following equations:
  • Ferrous iron Fe²⁺ + O₂ + 5/2 H₂O Fe(OH)₃ + 2H⁺
  • Ferric iron Fe³⁺ + 3 H₂O Fe(OH)₃ + 3 H⁺
  • Aluminum cation Al³⁺ + 3 H₂O Al(OH)₃ + 3 H⁺
  • Manganese cation Mn²⁺ + O₂ + H₂O MnO₂ + 2 H⁺

Overall: 4 FeS₂ + 15 O₂ + 14 H₂O 4 Fe(OH)³+ 8 H₂SO₄

• The untreated acid water also has a:
  • 3.43 pH level
  • Measured acidity at 92 mg CaCO/L
• The untreated acid water contains the following elements, according to ICP results:

	UNITS	COMPONENT	SAMPLE 1
SO	ppm	sulfate	502.74
Mg	ppm	magnesium	40.42
Al	ppm	aluminum	7.55
Na	ppm	sodium	12.62
Cl	ppm	chloride	18.28
Ca	ppm	calcium	101.7
K	ppm	potassium	5.89
Mn	ppm	manganese	1.74
Fe	ppm	iron	4.95