Question
A cast iron (Cp = 0.5 kJ / kg K) weighing 40 kg and a temperature of 450 C is cooled in 150 kg
A cast iron (Cp = 0.5 kJ / kg K) weighing 40 kg and a temperature of 450 ° C is cooled in 150 kg of oil (Cp = 2.5 kJ / kg K) at 25 ° C. If there is no heat loss, determine the entropy change: a. Iron b. Oil c. Total
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Principles of heat transfer
Authors: Frank Kreith, Raj M. Manglik, Mark S. Bohn
7th Edition
495667706, 978-0495667704
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