A certain reaction has an activation energy of 41.79 kJ/mol. At what Kelvin temperature will the reaction proceed 3.50 times faster than it did at 349 K? K T Calculate the rate constant, k, for a reaction at 61.0 C that has an activation energy of 83.5 kJ/mol and a frequency factor of 9.33 X 10 - $ K- TOOLS x10