Question: A converging lens (f = 6.0 cm) is located 15 cm to the left of a diverging lens (f = -3.0 cm). An object
A converging lens (f = 6.0 cm) is located 15 cm to the left of a diverging lens (f = -3.0 cm). An object is placed 18 cm to the left of the converging lens. What is the final image location of the object relative to the diverging lens? O 9 cm to the right of the diverging lens O 11 cm to the left of the diverging lens O 2 cm to the left of the diverging lens O 0.5 cm to the left of the diverging lens O 4 cm to the right of the diverging lens
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let u 4 v denoter the object and the image distonce respectively For conuergina lens f ... View full answer
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