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A distribution of values is normal with a mean of 1621.4 and a standard deviation of 32.6. Find the probability that a randomly selected value
A distribution of values is normal with a mean of 1621.4 and a standard deviation of 32.6.
Find the probability that a randomly selected value is greater than 1699.6.
P(X> 1699.6) =
Enter your answer as a number accurate to 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth.
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