A dust particle (M=5.0x10"kg) that carries charge Q=8.0x10 C is placed in between two parallel plates that are equally but oppositely charged at a distance of 4.0cm from the (-) plate. The strength of this constant (uniform) electric field is E=12,500 N/C. Find the work done as the field pushes Q toward the (-) plate through that distance of 4.0cm. 0.004J 400J 4.0J 0.524JIn the space between two vertical and parallel metallic plates that are oppositely charged one (+) and one (-), the electric field lines are horizontal and parallel indicating a constant E which magnitude and direction do not change as we go from one plate to another. If a point charge +Q is placed somewhere in this field, which answer is wrong? 24 it will be repelled from the (+) plate and attracted to the (-) plate. If the (+) plate is on the left and the (-) plate on the right, then +Q is pushed to 27 the right with a constant force of magnitude F = E Q because both E and Q are constants. Q does not accelerate to the right because F is constant. 30 Q accelerates to the right because the net force F is constant