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(a) Find the useful power output (in W) of an elevator motor that lifts a 2700 kg load a height of 30.0 m in

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(a) Find the useful power output (in W) of an elevator motor that lifts a 2700 kg load a height of 30.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg- so that only 2700 kg is raised in height, but the full 10,000 kg is accelerated. (Enter a number.) 6788.22 W (b) What does it cost (in cents), if electricity is $0.0900 per kW h? (Enter a number.) 1.54 cents

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