A laser with wavelength d/8 is shining light on a double slit with slit separation 0.300 mm . This results in an interference pattern on a screen a distance L away from the slits. We wish to shine a second laser, with a different wavelength, through the same slits. Part A What is the wavelength A, of the second laser that would place its second maximum at the same location as the fourth minimum of the first laser, if d = 0.300 mm ? Express your answer in millimeters. View Available Hint(s) v Hint 1. Second maximum and fourth minimum Use the location of the fourth minimum as the location of the second maximum to set up an expression relating 0.300 mm to Ay. Note that the value of sin() must be the same for each to put them in the same location. So, you can solve for sin(9) for each wavelength and set the results equal to each other. v Hint 2. Locating interference maxima and minima Recall that the locations of the interference maxima for a double-slit interference setup are given by dsin(0,,) = mA form =0,+1,+2,..., where 0, is the angle to the maximum, 0.300 mm is the separation between the slits, and )\\ is the wavelength of the light. Similarly, the locations of interference minima are given by the equation dsin(6,,) = (m -+ %) A for mI=1(=E1N-E2 9 IVl & O = ? Request