A part of lubrication system consists of two circular disks between which a lubricant flows radially. The 12

flow takes place because of a modified pressure difference P, - P; between the inner and outer radii r and

r2. respectively. Assuming steady state. laminar, incompressible Newtonian fluid Now, neglecting the

gravity effects and v;=Va=0 and v, is a function of r and 2 only. Consider only the region r r$ r and a

flow that is radially directed.

Show how the equation of continuity enables one to simplify the cquation of motion to give

dP

u di

r dz?

where * =r, is function of 2 only

(b) Solve above equation to get the following equation

0 = (P, - R.) + (NinE

did

(c) Show that further integration with respect 10 /2Nc

A part of lubrication system consists of two circular disks between which a lubricant flows radially. The flow takes place because of a modified pressure difference P.-P2 between the inner and outer radii n and 12. respectively. Assuming steady state. laminar, incompressible Newtonian fluid flow, neglecting the gravity effects and V2 = V0 and V is a function of rand Z only. Consider only the region srs and a flow that is radially directed. Fluid in Radial flow outward between disks (a) Show how the equation of continuity enables one to simplif the equation of motion to give de do drrdza where =rvis function of only (b) Solve above equation to get the following equation d? 10 = (P. P.) + (u inau) dz? (c) Show that further integration with respect to / DO (2) = ( PP) Zurin (la) [-(3)