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A particle of mass 0.2 kg has a position vector 7 = 20t + (15t - 5t2). When t = 2 seconds. 4) Find
A particle of mass 0.2 kg has a position vector 7 = 20t + (15t - 5t2). When t = 2 seconds. 4) Find the angular momentum with respect to the point fo = 60. A) -60k (J.s) B) 60k (J.s) C) -20k (J.s) 5) Find the torque with respect to the point 70 = 601. D) 30k (J.s) E) 80k (J.s)
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Fundamentals of Physics
Authors: Jearl Walker, Halliday Resnick
8th Extended edition
471758019, 978-0471758013
