Question
A particle with charge q = 33.4 mC and mass m = 7.18 mg has a kinetic energy of K = 4.84 mJ and
A particle with charge q = 33.4 mC and mass m = 7.18 mg has a kinetic energy of K = 4.84 mJ and is moving counter-clockwise on your screen on a circle of radius R = 80.0 cm. a. b. C. d. What is the speed of this particle? What is the magnetic field that it is sitting in? A field out of the screen will be positive and a field into the screen will be negative. What is the cyclotron angular frequency w of this proton? If we were to double the kinetic energy K and double the magnetic field B, what would be the new radius of the path?
Step by Step Solution
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a To find the speed of the particle we can use the formula for kinetic energy K12mv2 where m is the ...Get Instant Access to Expert-Tailored Solutions
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College Physics
Authors: Jerry D. Wilson, Anthony J. Buffa, Bo Lou
7th edition
9780321571113, 321601831, 978-0321601834
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