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A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a

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A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radius of 50 feet. What is the height of the rider from the ground after the Ferris wheel rotates 1 17 radians? 12 (50 cos 0, 50 sin 0) 115 12 50 ft. 15 ft starting point O A. " (-V2 + V6 ) + 65 O B. 25 2 (-V2 +V6)O C. 25 2+16 O D. 25 V2+16)+65 NA person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates radians? 12 (20 cos 0, 20 sin #) ending point 12 starting 20 ft. pointO A. (5( 2-V6), 5( 2+V6)) O B. (5( V2+V6),5(-V2+V6)) O C. (5 ( V2+ V6 ), 5( v2-V6) O D. (5 ( -V2 + V6), 5(V2+v5)A student was asked to prove cos(x + 7) = - cos x. The student's work follows. cos( x + 7) = cos x cos / + sin x sin / = - cos x Where was the student's mistake? O A. The second expression should be cos xsin * + sin xcos * . O B. The second expression should be cos x cos x - sin xsin * . O C. The second expression should be cos xsin x - sin xcos * . O D. The second expression should be cos xsin x + sin xsin * .Which identity needs to be used to prove tan - x = cot x? O A. Apply tan(a- B) = tan @-tan B 1 + tan cutan 8 O B. Apply tan 8 = sin & cos & O C. Apply tan(-x) = -tan x . O D. Apply cos(a- B) = cos acos B + sin @sin B.Prove csc - x = sec x . O A. CSC - X = sec x sin -cos x + cos sin x 2 O B. CSC - X = secx sin - sin x - Cos - COS X O C. CSC X E = sec x sin - sin x + cos COS X 2 O D. CSC - X = = secx sin - cos x - Cos - - sin x

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