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A proton is moving with velocity v = (Vx i + Vz k) m/s, where Vx = 6.70 x 103 and Vz = 5.50 x

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A proton is moving with velocity v = (Vx i + Vz k) m/s, where Vx = 6.70 x 103 and Vz = 5.50 x 103. The instant it enters a uniform magnetic field it experiences a magnetic force in the positive y-direction of 2.70 x 10-5 N. [Charge of proton q = 1.602 x 10-19 c. ] To begin, compose an equality for this problem given FB = q vxB, such that each of the vectors is expressed as a vector sum of perpendicular (x/y/z) components. For example, B = Bxi + By j + Bzk. a.) If there is no x-component of the magnetic field (By = 0), what is the y-component of the magnetic field? By = 0 b. ) What is the magnitude and direction of the z-component of the magnetic field? BZ = ( - y k )

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