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A stone is launched vertically upward from a cliff 448 ft above the ground at a speed of 48 ft/s. Its height above the
A stone is launched vertically upward from a cliff 448 ft above the ground at a speed of 48 ft/s. Its height above the ground t seconds after the launch is given by s=-16t2 +48t+448 for 0 st7. When does the stone reach its maximum height? Find the derivative of s.
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