A student sets up the following equation to solve a problem in solution stoichiometry.

$($The $?$ stands for a number the student is going to calculate.$)$

Enter the units of the student's answer.

$\frac{(0\mathrm{.}38(L))(\frac{1(mL)}{{10}^{-3}(L)})(1\mathrm{.}81\frac{g}{mL})}{(139\mathrm{.}34\frac{g}{\text{m}\text{o}\text{l}})}=$