a$)$ Using a $2-$year moving average, the forecast for year $6=200$ miles $($round your

response to the nearest whole number$).$

b$)$ If a $2-$year moving average is used to make the forecast, the MAD based on this $=$

miles $($round your response to one decimal place$).($Hint: You will have only $3$ years

of matched data.$)$

c$)$ The forecast for year $6$ using a weighted $2-$year moving average with weights of $0\mathrm{.}35$

and $0\mathrm{.}65($the weight of $0\mathrm{.}65$ is for the most recent period$)=$ miles $($round your

response to the nearest whole number$).$

The MAD for the forecast developed using a weighted $2-$year moving average with

weights of $0\mathrm{.}35$ and $0\mathrm{.}65=$ miles $($round your response to one decimal place$).($Hint:

You will have only $3$ years of matched data.$)$

d$)$ Using exponential smoothing with $=0\mathrm{.}50$ and the forecast for year $1$ being $3,000,$

the forecast for year $6=$ miles $($round your response to the nearest whole number$).$help

help