A water tank is placed on top of a hill, as shown in the Figure 8. The level of water in the tank is maintained at 5.0 m high at all times. The length of the pipe shown is 100 m, and the inclination of the pipe is 60 (degrees). Note: The atmospheric pressure is Pty = 1.013 x 10 Paand Puiater = 1.0 X 103 kg/m3. Determine the pressure of the water at the bottom level of the building? Figure 8 Hint: Use trigonometry to find the height from the bottom of the tank to the ground level. Then add the water level height to get the total vertical height (h). Figure 9 below shows a nozzle carrying chemicals used for etching wafers from ground level 1 to the semiconductor lab at Level 2 as shown. The pressure at Level 1 is 1.25 x 10 Pa, the velocity is 0.55 m/s, and the diameter of the pipe at Point 1is 0.01m. Given that the diameter at Point 2 is 0.005 m and Level 2 is at height of 9 m from Level 1. _f_ - 4 Figure 9 Write down all the variables (Known and Unknown): P1= V4.7 1= A1=T{T12= P2= Vg = rp= A2=7TI'22= A. What is the velocity to the nearest hundredth of am/s at Level 2? Hint: Apply flow continuity formula/ principle to calculate v. B. InProblem 9, what is the pressure in Pa (Pascal) at Point 2? Apply Bernoulli's Principle to calculate Po