A weight of $80lb$ stretches a spring $3ft.$ The weight is pulled down $5ft$ below the equilibrium position and then released. What initial

velocity $v_0$ given to the weight would have the effect of doubling the amplitude of the vibration? Use $g=32f\frac{t}{se{c}^2}.$

$v_0=f\frac{t}{sec}$

$($Type an exact answer, using radicals as needed.$)$