A year in the modern Gregorian Calendar consists of $365$ days. In reality, the earth takes longer to rotate around the sun. To account for the

difference in time, every $4$ years, a leap year takes place. A leap year is when a year has $366$ days: An extra day, February $29$th$.$ The

requirements for a given year to be a leap year are:

The year must be divisible by $4$

If the year is a century year $(1700,1800,$ etc.$),$ the year must be evenly divisible by $400$ ; therefore, both $1700$ and $1800$ are not leap years

Some example leap years are $1600,1712,$ and $2016.$

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

$1712$

the output is:

$1712-$ leap year

Ex: If the input is:

$1913$

the output is:

$1913-$ not a leap year

$553120\mathrm{.}2501028.q3zqy7$

LAB

ACTIVITY

$4\mathrm{.}12\mathrm{.}1$: LAB: Leap year

$\frac{0}{10}$

main.py

Load default template...

$1$ is$\_$leap$\_$year $=$ False

input$\_$year $=$ int$($input$())$

$5\text{'}\text{'}\text{'}$ Type your code here. $\text{'}\text{'}\text{'}$