A2 - Position graph Position I6X l2X 8X 4X 0 t 0 T 2T 3T 4T The graph above shows the position as a function
A2 - Position graph Position I6X l2X 8X 4X 0 t 0 T 2T 3T 4T The graph above shows the position as a function of time for an object accelerating from rest starting att = 0. The acceleration is constant and the motion is along a straight line. This would fit the motion for many situations, such as you dropping something from rest and it falling under the influence of gravity, or a car accelerating once a traffic light turns green. K\" Open i @ Part(a) Homework Answered Due Sep 19th,12:15 PM 0 Six possible velocity vs. time graphs are shown. Defining v = X/T, which velocity graph is consistent with the position graph shown above? Velocity 8v 6v 4v 2v 0 1: 2T 4T Graph A Velocity Gra h D 8v 6v 4v 2v 0 t 2T 4T Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. Velocity 8v 6v 4v 2v 0 t. 2T 4T Graph B Velocity 8v 6v 4v 2v 0 t 2T 4T Graph E Velocity 8v 6v 4v 2v 0 t. 2T 4T Graph C Velocity 8v 6v 4v 2v 0 t 2T 4T .1 7' Open it Graph F Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Graph A Your answer b Graph B C Graph C d Graph D e Graph E f Graph F Answered - Correct! . 0 attempt left Resubmit@ Part (b) o Homework I Answered I Due Sep 19th,12:15 PM Use these nu mbers for the rest ofthe problem. X = 4.00 m and T = 1.00 5. Calculate the magnitude of the acceleration. a = m/s2 Type your numeric answer and submit You are correct Answered Correct! - 3 attempts left ,4 Resubmit @ Part(c) 0 Homework I Answered I Due Sep 19th,12:15 PM Let's say the motion continues beyond 4T with the same acceleration. At t = 5T, what total distance will have been traveled? x = m Type your numeric answer and submit so X You are incorrect K" Open in Readi Part (d) A Homework . Answered . Due Sep 19th, 12:15 PM At that same time, what is the object's speed? m/s Type your numeric answer and submit 20 X You are incorrect Answered - Incorrect . 3 attempts left Resubmit
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