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According to a study published in a reputable science magazine, about 7 women in100,000 have cervical cancer(C), so P(C)equals=0.00007 Suppose the chance that a Pap

According to a study published in a reputable science magazine, about 7

women in100,000 have cervical cancer(C), so P(C)equals=0.00007

Suppose the chance that a Pap smear will detect cervical cancer when it is present is 0.88

Therefore,Upper P left parenthesis test pos|C right parenthesisP(testpos|C)equals=0.88

What is the probability that a randomly chosen woman who has this test will both have cervical cancer AND test positive forit?

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