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Aluminum chloride can be formed from its elements: 2Al(s) + 3Cl(g) 2AICI 3(s) AH = ? Use the reactions here to determine the AH for
Aluminum chloride can be formed from its elements: 2Al(s) + 3Cl(g) 2AICI 3(s) AH = ? Use the reactions here to determine the AH for reaction (i): (HCI(g) HCl(aq) AH (ii) = -74.8 kJ (H(g) + Cl(g) - - - 2HCl(g) AIC13(aq) AIC13(s) W 2Al(s) + 6HCl(aq) overall AH) = -185 kJ AH() = +323 kJ/mol - 2AlCl3(aq) + 3H(g) AH) = -1049 kJ
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Biochemistry
Authors: Mary K. Campbell, Shawn O. Farrell
8th edition
9781305176621, 1285429109, 1305176626, 978-1285429106
