AN$05$

$"315$ K $180035\%$CaCl $2$ SwensonWalker $300$ K $$ CaCl $2$H$26300$ K $20$ kgCaCl$/100$ kgH $2$ O $12300$ kJ$/$kmol $($Cp$)4\mathrm{.}18$ kJ$/$kgK $133\mathrm{.}5$ kJ$/$kg $280$ K $290$ K $$ U $0\mathrm{.}15$ kW$/$m $2$ K $1\mathrm{.}5$ m $2/$m $$ Ca$=40$ g$/$mol

$1."$