An adventure company runs two obstacle courses, Fundash and Coolsprint, with similar designs. Since Fundash was built on rougher terrain, the designer of the courses suspects that the mean completion time of Fundash is greater than the mean completion time of Coolsprint. To test this, she selects 265 Fundash runners and 220 Coolsprint runners. (Consider these as independent random samples of the Fundash and Coolspring runners.) The 265 Fundash runners complete the course with a mean time of 78.2 minutes and a standard deviation of 5.6 minutes. The 220 individuals complete Coolsprint with a mean time of 76.6 minutes and a standard deviation of 6.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of signicance, is there enough evidence to support the claim that the mean completion time, \"1' of Fundash is greater than the mean completion time, \"2' of Coolsprint? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to at least three decimal places. (If necessary, consult a list of formulas.) Carry your intermediate computations to at least three decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H. p Ho : 0 X S P H 1 : 0 (b) Determine the type of test statistic to use. Degrees of freedom: 0=0 030 020 (c) Find the value of the test statistic. (Round to three or more decimal places.) 0*0 00 0 X 5 ? (d) Find the p-value. (Round to three or more decimal places.) (e) Can we support the claim that the mean completion time of Fundash is greater than the mean completion time of Coolsprint? Yes ONo