An electron and a proton, each starting from rest, are accelerated by the same uniform electric field ofA proton enters the uniform electric field produced by the two charged plates shown in the

figure. The plate length is $L=10\mathrm{.}0cm.$ The magnitude of the electric field is

$5\mathrm{.}0{10}^5\frac{N}{C},$ and the speed of the proton when it enters is $1\mathrm{.}7{10}^7\frac{m}{s}.$

What distance $d$ has the proton been deflected downward when it leaves the plates? Give

you answer in units of $mm.$

$d=$ number $(rtol=0\mathrm{.}03,$ atol $=0)$

$280\frac{N}{C}.$ Determine the distance $d$ and time $t$ for each particle to acquire a kinetic energy of $4\mathrm{.}0{10}^{-15}J.$

Electron:

Part $1$

$d_e=$ number $(rtol=0\mathrm{.}03,$ atol $=0)$

m

Part $2$

$t_{\text{u}\text{a}\text{r}\text{r}}=$ number $(rtol=0\mathrm{.}03,$ atol $=0)$

Proton:

Part $3$

$d_p=$ number $(irtol=0\mathrm{.}03,$ atol $=0)$

m

Part $4$

$t_0=$ number $(rtol=0\mathrm{.}03,$ atol $=0)$