An investment yields $500 per year compounded continuously for 12 years at 10% interest. What is the (future) value of this income stream at the end of 12 years? Which expression is equal to the future value of a continuous income stream of K dollars per year for N years at interest rate r compounded continuously? O A . Ker.N "ldt OB. Ker(N- D dt Oc. Ke ". N - 1 dt OD . Ke " (N + D) at What is the value of K? K = What is the value of N? N= What is the value of r? r=(Type an integer or a decimal.) Substitute the determined values for K, N, and r into the expression for the future value of a continuous income stream of K dollars per year for N years at interest rate r compounded continuously. Choose the correct answer below. O A. 500 e 0.1 . 12 . dt 0 B. 500 e 0.1(12 -9) at 12 O C. 500 e 0 1(12 +1) at OD. 500 e 0.1 . 12 -1 at 0 Find an antiderivative of the result from the previous step The antiderivative is ( ) |. Evaluate the antiderivative over the interval. This will be the future value of this income stream at the end of 12 years. The value of the antiderivative over the interval is Simplify your answer. Round to the nearest cent as needed.)