An irregular example of 100 understudies is taken from the number of inhabitants in all low maintenance understudies in the U.S., for which the general populace of females is 0.6.

n=100

p=0.6

1) Test to check whether we can utilize the typical dissemination.

np= Answer and nq= Answer

2) Since the populace extent is p=0.6, we know the mean of the examining extents is

p= Answer

3) What is the standard deviation?

p^= Answer (Round to the closest thousandth.)

A review was taken at a nursing home with respect to inclinations in music and it was discovered that:

12 tune in to western

11 tune in to old style

14 tune in to jazz

8 tune in to western and jazz

9 tune in to jazz and old style,

5 tune in to western and old style

8 tune in to none of these

3 tune in to every one of the three.

What number of individuals were reviewed?

The extent of left-gave individuals in everybody is about 0.1. Assume an irregular example of 225 individuals is noticed.

1) What are guess esteems, mean of test extent, and standard blunder?

np= Answer and nq= Answer

p= Answer

p= Answer

2)

What span is practically sure (likelihood 0.997) to contain the example extent of left-gave individuals?

The example extent is practically sure to be among ______ and ________.

3)

a) Find the rough likelihood of in any event 30 of every 225 of being left-given. What is the example extent?

p= Answer (Round to the closest 100th.)

b) What is the z-score?

P(p 0.13) = P(z Answer )

4) Find the likelihood utilizing the ordinary table (opens in new window).

P(p^ 0.13) = P(z 1.5) = Answer

The yearly compensation for a specific occupation has a typical circulation with a mean of $54,000 and a standard deviation of =$5000. What is the likelihood that the mean compensation of arbitrary example of 100 specialists is close to $54,215?

1)

x= Answer (Do exclude the dollar sign)

x= Answer

..1..

2) Fill in spaces.

P(x ___ 54,215) = P(z __ ______) = ____________

3)There is a(n) _____% chance that the mean size of an irregular example is close to $54,215.