Question: Analyze the following, what is the time complexity? n int fun(int n) { nlog(n-1) n-1 One } int count = 0; for (int i=
Analyze the following, what is the time complexity? n int fun(int n) { nlog(n-1) n-1 One } int count = 0; for (int i= 0; i 0; j--) count = count + 1; return count; Important Summation Formulas 1. =1+1+in+1=x-1+14, u are integer limits,/ 2 i=1+2+. +1= 7. Durat +=+++ 4+1 k+1 th m(n + 1)(2n + 1) 6 =12+2.25 + *(x+1) $ d=1+a+-+0 (a #1); 2=2+1-1 1-0 I- 21-2+2-2++2=(n-1)2++2 8 nlga Sum Manipulation Rules 1. =1+ Innty, where y 0.5772 ... (Euler's constant) ? b)=+ 3 -+ , wherel
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