Answer quickly for thumbs up

Answer is

CO+H2O(v)CO2+H2;Hr=41.15kJmol1at25C The product gas contains 40 mole\% H2,40%CO2 and 20%H2O and leaves at a rate of 112molh1 and 500C. The product gas is then cooled in a condenser to 15C and 1 atm where some of the water condenses. The mole fraction of the water vapour in the gas leaving the condenser is 0.0168 . Calculate (a) the \% excess steam fed to the reactor. (5 marks) (b) the rate of condensation of the water in the condenser (molh1) (5 marks) (c) the rate of heat removal from the reactor ( kW) (15 marks) Data Heat Capacity Cp=a+bT where Cp(Jmol1C1) and T(C) 50%, (b) 20.87molh1 (c) 0.037kW