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AP CALCULUS STUDENT HANDOUT Practice with the Mean Value Theorem Recall that the Mean Value Theorem (MVT) states that if f(x) is continuous on the
AP CALCULUS STUDENT HANDOUT Practice with the Mean Value Theorem Recall that the Mean Value Theorem (MVT) states that if f(x) is continuous on the interval [a, b] and differentiable on the interval (a, b) , then for at least one value of c in (a, b), f'(c) =_)(). In words, b - a at some point in the interval the instantaneous rate of change is equal to the average rate of change over that interval. Graphs of three functions with domain [1, 3] are shown in the following table. Explain why the Mean Value Theorem does not apply for any of these functions on the interval [a, b]. y = f ( x ) Why the MVT does not apply to fon [1, 3] A. y = f ( x ) 0 2 3 4 B. 4 - y = f ( x ) 3 - 2 1 - 0 2 3 C. y = f (x ) 3 - N 10 2 3 CollegeBoard 2017 College Boardestion 2 antiable. A graph of the net graph to ans er these questions: which of any ection points of g(x)? AP CALCULUS 6. f(x) = tan #x 7. 1(x )-x4 +3, x51 2x +2 x> 1 Graph of y = 91x), thec (This graph has a horizontal t1043 SF s concurity STUDENT HANDOUT Let's look at the regula caltaron. DuoSJOd S Concavity and Inflection Notice that the 'noso these peal nok waym post i paau now you suedw Write the ys!Ibu3 meaning of sentences in Use the above c and that the action was lotice that the endings underlined part) of the v using the Conjugate these verbs verb chart: and that f(x) = (x - 1)2 (x - 2). Which x-values have f"(x) =0? What action points of ?? derivative of g, that is, y = g'(x), STUDENT HANDOUT -values have g"(x) =0, and what AP CALCULUS Does the Mean Value Theorem apply? For each of the following functions described below, determine whether the Mean Value Theorem can be applied on the interval [-3,3) . If it can be applied, explain how you know. If it cannot be applied, explain why not. 1 Example: f(x) is a function differentiable for all real numbers. Answer: The MVT can be applied. Since the function is differentiable for all real numbers, it is also 2 continuous for all real numbers. So it is certainly continuous on [-3,3] and differentiable on 4 (-3, 3). 1. f(x) is continuous for all real numbers. f g(x) x =-2.) 2. f(x) is differentiable on (-3, 3). 3. f ( x ) = x 23 4. f ( x) = /x/+ 4 5 . f ( x ) = sin * x (3 CollegeBoard 2017 College Board
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