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Applied Maths (10%) (Order of convergence) Assume we have a sequence 1 3:2 $n+1= $n( f): a > 0, (1) (a) (4%) If an is

Applied Maths

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(10%) (Order of convergence) Assume we have a sequence 1 3:2 $n+1= $n( f): a > 0, (1) (a) (4%) If an is a suitably close to (/5, show that this sequence has a limit \"Inntoo 3n = a (b) (6%) What is the convergence order of the sequence (1)? Give the proof

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