Aqueous hydrobromic acid $(HBr)$ reacts with solid sodium hydroxide $(NaOH)$ to produce aqueous sodium bromide $(NaBr)$ and liquid water $(H_{2}O).$ If

$0\mathrm{.}146g$ of water is produced from the reaction of $4\mathrm{.}0g$ of hydrobromic acid and $1\mathrm{.}2g$ of sodium hydroxide, calculate the percent yield of water.

Be sure your answer has the correct number of significant digits in it$.$