Assignment No. 2 CCCN-222 Signals and Systems Q. No. 2: What is the upper limit and lower limit of the time-index for which the output y[n] is nonzero. Name: Registration Number: Submission Guideline: Upload a PDF document (scanned or word document) on the Blackboard. Q. No. 3: Determine and plot the convolution sum y[n] (see Q. No. 1) using Octave. You can follow Please mention your name and registration number. the following steps, and show the Octave output for each step: Use Octave to determine the signals and plot them as required. Octave can either be installed on the j) Define the array x=[1,2,2,4,2,1] computer (https://www.youtube.com/watch?v=e2Ypm-fNVIA\&ab_channel=NPTEL-NOCIITM ) or accessed online at the following link: https://octave-online.net/ ii) Define the array h=[1,1,1,1,1,1] Consider the signal shown x[n] defined as follows: x[0]=1,x[1]=2,x[2]=2,x[3]=4,x[4]=2,x[5]=1. iii) determine the output array y=conv(x,h) Assume that x[n]=0, otherwise. The signal x[n] is passed through a discrete-time LTI system with impulse response h[n] given as h[0]=1,h[1]=1,h[2]=1,h[3]=1,h[4]=1,h[5]=1. iv) Define a time vector using upper and lower limit from Q. No. 2, e.g., t=[0:10] Assume that h[n]=0, otherwise. Q. No. 1: Use graphical convolution method to find the zero-state response y[n]. Hint: The zero-state response y[n] is given as the convolution sum of x[n] and h[n], i.e., y[n]=x[n]h[n]. v) Plot the output y against time t by using the stem() function, e.g., stem(t,y) [insert plot here] vi) What is the difference between the stem() and plot() function