Assuming that the fractional part is to be stored in 3 bits, write down the value of each of the two guard digits and the value of the sticky digit.

Now consider the binary number 0.0010011101.

 

First guard digit 0 0 1 1 1 1 Second guard digit 0 1 1 0 0 1 1 Sticky digit 1 0 1 0 1 0 1 0 truncate 1 round up 0 0 0 0 1 1 1