At 1741C the equilibrium constant for the reaction: 2IBr(g)I2(g)+Br2(g) is Kp=7.54e01. If the initial pressure of IBr is 1.94e03atm, calculate the equilibrium partial pressures of IBr6I2, and Br2. Pick the choice which gives the correct value for the equilibrium partial pressure of one of these gases. a) PBr(eq)=3.08e04atm b) P12(eq)=2.46e03atm c) PBr2(eq)=6.16e04atm d) P18r(eq)=1.23e03atm e) P12(eq)=1.54e04atm