At $7\mathrm{.}05$ cents per kilowatt$-$hour, what does it cost to operate a $11\mathrm{.}0hp$ motor for $6\mathrm{.}00hr?$

Express your answer in dollars.

Previous Answers

Correct

Set Up: Since the electricity cost rate is given in cents per $kWh,$ each power must be multiplied by

corresponding time usage in determining the cost: cost cost $\frac{?}{Pt}$

Solve:

$cost=Pt(\frac{cost}{Pt})=[(11\mathrm{.}0hp)(6\mathrm{.}00hr)(\frac{746(W)}{hp})(\frac{kW}{1000(W)})](\frac{7\mathrm{.}05}{kWh})=347=$

Part B

At $7\mathrm{.}05$ cents per kilowatt$-$hour, what does it cost to leave a $75\mathrm{.}0W$ light burning $24\mathrm{.}0$ hours a day?

Express your answer in dollars.