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At 938C the equilibrium constant for the reaction: 2IBr(g)I2(g)+Br2(g) is Kp=1.63. If the initial pressure of IBr is 0.00620atm, what are the equilibrium partial pressures

At 938C the equilibrium constant for the reaction: 2IBr(g)I2(g)+Br2(g) is Kp=1.63. If the initial pressure of IBr is 0.00620atm, what are the equilibrium partial pressures of IBr,I2, and BrI2 ? p(IBr)= p(12)= p(Br2)=

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