At very low temperatures the molar heat capacity of rock salt varies with temperature according to Debye's T law: C = k where k = 1940J/(mol K) and 0 = 281K. Part A How much heat is required to raise the temperature of 1.50 mol of rock salt from 11.0 K to 36.0 K? (Hint: Use the equation dQ = nCdT and integrate.) Express your answer in joules. Q = 54.6 J Submit Previous Answers Part B Correct What is the average molar heat capacity in this range? Express your answer in joules per mole-kelvin. Caverage 36.4 Submit Previous Answers Request Answer Incorrect; Try Again; 3 attempts remaining Part C What is the true molar heat capacity at 36.0 K? Express your answer in joules per mole-kelvin. C 4.08 J/(molK) ? J/(mol-K)