Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Attempting to prove closure under multiplication. Is this correct? Proof of closure under scalar multiplication Multiply vector x by scalar k the result is a
Attempting to prove closure under multiplication. Is this correct?
Proof of closure under scalar multiplication
Multiply vector x by scalar k the result is a real value that is in subspace W. 3 * x = 3x
K* (x , 3x) = (kx , k*3x) by multiplication of a vector and a scalar (kx , k*3x) = (kx, 3*kx) By the commutative property of multiplication
The coordinate (kx, 3*kx) is in W since the components,the scalar K and the vector x, 3x are all real when it is multiplied by a real number the result is in subspace W.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started