b) Calculate ionic strength (Im), mean activity coefficient (Yt), and activity of KsFe(CN). (ak.Fe(cs).) (in terms of {[(ax+)*][(a[Fe(CN))--)'}}) for a 0.0250 molal solution of KaFe(CN)at 298 K. Assume complete dissociation. Given that a=vxm, me = 1 mol kg?. Quantities a, Yu and m denote activity, mean activity coefficient and concentration. logy+ = -12,2_JA/T, A = 0.509 for aqueous solution at 25C