B. We have found that coordinates of the letter \"H\" are 40 51.485' N, 74 12.080' W, and the coordinates of the manhole cover are 40 51 .800' N, 74 11.883' W. So, we have a right triangle with the points (40 51 .485' N, 74 12.080' W; 40 51.800' N, 74 11.883' W; 40 51.485' N, 74 11.883' W). The length ofthe side A (40 51.485' N, 74 12.080' W; 40 51.485' N, 74 11.883' W) is 910.97 ft. The length ofthe side B (40 52.117' N, 74 11.711' W; 40 51.593' N, 74 11.711' W) is 1910.99 ft. Hence, the straightline distance is 1n C = 910.97 2 + 1910.992 = 2117.01 ft = 2117.01 ft X 12 ft cm = 25404.17 in = 25404.17 in X 2.54_ = 64526.59 cm 1n = 645.26 In