Background information:

Bx=(4/5)3/20NI/RBx=(4/5)3/20NI/R For a Helmholtz coil pair carrying current II in N turns of wire on a radius RR separated by RR this formula allow us to compute the field at the central point where our test magnet hangs by a thread.

Radius in cm = 10

Distance from the midpoint to the plane of either coil in cm = 5

Number of turns of wire on each coil = 200

Number of coils = 2

For each entry in the table calculate the magnetic field in microtesla (10^-6 T)at the center of the coil where the magnet is suspended using the Helmholtz coil formula for Bx of a Helmholtz coil given on the class website.

Helmholtz Coil Current	Number of Oscillations Observed	Time Stamp of Oscillation (Elapsed Time)	Frequency of Oscillation
0.07 A (1 V)	7	14:18-14:36 (18 s)	7/18 = 0.39 Hz
0.15 A (2 V)	15	14:47-15:18 (31 s)	15/31 = 0.48 Hz
0.22 A (3 V)	13	15:27-15:49 (22 s)	13/22 = 0.59 Hz
0.29 A (4 V)	14	16:05-16:25 (20 s)	14/20 = 0.70 Hz
0:43 A (6 V)	15	16:40-16:58 (18 s)	15/18 = 0.83 Hz
0.57 A (8 V)	15	17:16-17:32 (16 s)	15/16 = 0.94 Hz
0.72 A (10 V)	15	17:42-17:56 (14 s)	15/14 = 1.07 Hz
0.86 A (12 V)	15	18:06-18:18 (12 s)	15/12 = 1.25 Hz
1.00 A (14 V)	15	18:34-18:45 (11 s)	15/11 = 1.36 Hz