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Barium sulfate, BaSO4 (s) forms in the following reaction : a(NO3) 2 (aq) + Na2SO4 (aq) to form BaSO4 (s) + 2NaNO3 (aq).If 75.00g of

Barium sulfate, BaSO4 (s) forms in the following reaction : a(NO3) 2 (aq) + Na2SO4 (aq) to form BaSO4 (s) + 2NaNO3 (aq).If 75.00g of barium nitrate Ba(NO3) (aq) , reacts with 100.00 g of sodium sulfate, NaSO4(aq) what is the theoretical yield

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