Question: Box answers please Antireflective Coating Problem 18.10 A thin film of polystyrene is used as an antireflective coating for fabulite (known as the substrate). The

Box answers please

Box answers please Antireflective Coating Problem 18.10 A thin film of polystyrene

Antireflective Coating Problem 18.10 A thin film of polystyrene is used as an antireflective coating for fabulite (known as the substrate). The index of refraction of the polystyrene is 1.49, and the index of refraction of the fabulite is 2.409. Light of 570 nm wavelength illuminates two slits that are 0.25 mm apart. shows the intensity pattern seen on a screen behind the slits Light rays Air 3422, 1:06 PM Homework & Polystyrene 1 = 1.49 Fabulite n = 2.409 Part A What is the minimum thickness of film required? Assume that the wavelength of the light in air is 510 nanometers. Express your answer in nanom You did not open hints for this part. Part A ANSWER: What is the distance to the screen? Express your answer with the appropriate units nm ANSWER: Problem 18.9 Problem 18.19 Pigeons and doves have iridescent feathers around their necks . The color is produced by a 330-nm-thick layer of keratin (n = 1.56) with air on both sides that is found around the edge of the feather barbules. A commercial diffraction grating has 400 lines per mm. Part A Part A When a student shines a 490 am laser What wavelength or wavelengths of visible light are strongly reflected by this structure? grating? Express your answer in nanometers. If there is more than one answer, enter each answer separated by a comma. Express you answer as an integer. ANSWER: ANSWER: * = nm Number of bright spots Problem 18.17 Problem 18.25 Two narrow slits are 0.12 mm apart. Light of wavelength 550 nm iluminates the slits, causing an interference pattern on a screen 1.0 m away. Light from each s in = 1 maximum on the right side of the of the central maxim Part A How much farther did the light from the left slit travel than the light from the right slit? Express your answer in nanometers. 14/22. 1:06 PM ANSWER: pattern can give a measurement of the length of the san some enhance screen the hopes. This has been Ar = nm sarcomeres lengthen and shorten. In one case, an investig howit water back and forth through a 100" angle, then stretching the muse's, The resuming diffraction pageant measured the distance between the two m = 2 fringes on either sic of the central maximum. This length varied from 1.9 can to 2.7 cm. Part A What were the minimum and m Express your answers in micrometers in ascending order separated by a comma

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