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Calculate G for the reaction 1/2(O 2 ) = [O] Fe wt% at 1650C. Given: (H 2 ) + 1/2(O 2 ) = (H 2

Calculate G for the reaction 1/2(O₂) = [O]_{Fe wt%} at 1650C.

Given: (H₂) + 1/2(O₂ ) = (H₂O) G = 251790 + 55.5T Joules

(H₂) + [O]_{Fe wt%} = (H₂) logk = 7040 /(T ^3.5)

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