Calculate the reduced paid$-$up insurance for Lee Chin, age $38,$ who purchased a $$390,00020-$payment life policy. At the end of year $10,$ Lee stopped paying premiums. $($Use Table $20\mathrm{.}2.)$

Reduced paid$-$up insurance

TABLE $20\mathrm{.}2$

Nonforfeiture options based on $$1,000$ face value

$\backslash$table$[[\backslash$table$[[$Years$],[$insurance$],[$policy in force$]],$STRAIGHT LIFE,$20-$PAYMENT LIFE,$20-$YEAR ENDOWMENT$],[\backslash$table$[[$Cash$],[$value$]],\backslash$table$[[$Amount of$],[$paid$-$up$],[$insurance$]],\backslash$table$[[$EXTENDED$],[$TERM$]],\backslash$table$[[$Cash$],[$value$]],\backslash$table$[[$Amount of$],[$paid$-$up$],[$insurance$]],\backslash$table$[[$EXTENDED$],[$TERM$]],\backslash$table$[[$Cash$],[$value$]],\backslash$table$[[$Amount of$],[$paid$-$up$],[$insurance$]],\backslash$table$[[$EXTENDED$],[$TERM$]]],[$Years$,$Days,Years,Days,Years,Days$],[5,29,86,9,91,71,220,19,190,92,229,23,140],[10,96,259,18,76,186,521,28,195,319,520,30,160],[15,148,371,20,165,317,781,32,176,610,790,35,300],[20,265,550,21,300,475,1,000,,$Life,$1,000,1,000,,$Life$]]$

Option $1$: Cash value

$$200,000$$$1,000=200$$$148=$$$29,600$

Option $2$: Reduced paid$-$up insurance

$$200,000$$$1,000=200$$$371=$$$74,200$

Option $3$: Extended term insurance

Bob could continue this $$200,000$ policy for $20$ years and $165$ days.