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Can I get help with solving these please 1. Consider the vectors u = and 7 =. (1). (5pt) Assume u and v intersect at

Can I get help with solving these please

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1. Consider the vectors u = and 7 =. (1). (5pt) Assume u and v intersect at an angle 0. Find cos . (2). (10pt) Find the equation of the plane parallel to the vectors u and v, passing through the point (-3, 0, 0).2. A particle starts to move from (0,0,0) and has acceleration @(t) = with an initial velocity of at t = 0. (1). (5pt) Find the velocity (2). (2). (5pt) Find the position 7(t). (3). (5pt) When does the particle hit the plane z = /57 3. (1). (9pt) Find the length of the following curve. Flt) =, 4 . \f5. Consider the surface f(z,vy,2) = z%y + y22. (1). (10pt) Find the (three-dimensional) gradient of f at the point (1,2,6). (2). (bpt) Given the unit vector & =, find the directional derivative of f at (1,2,6) in the direction of 4. 6. (1). (10pt) Find the tangent plane T to the surface z = x2 + y' + xy at the point (0, 1, 1). (2). (5pt) Where does T intersect the y-axis?7. Suppose that f(x, y) = 28 272. Now consider the limit: M = lim f (x, y) . (x,y)-(0,0) Which of the following statements is true? A. The limit exists because the limit along the path y = x is 0. B. The limit exists because the limit along the path y = x is -2. C. The limit M is co. D. The limit does not exist because the limit along x-axis is 0, but the limit along y-axis is -2. E. The limit along y = x2 is 4. 8. Let f(u, v) = Vu2 + 12, where u = u(x, y) and v = v(x, y). If u(2, 1) = 1, ux(2, 1) = 5, v(2, 1) = 0, vx(2, 1) = 6, find on at (x, y) = (2, 1). A. 1 B. 5 C. V5 D. 5 E. 8

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